21 lines
347 B
MySQL
21 lines
347 B
MySQL
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SELECT
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x.id AS id,
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x.name AS name,
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(
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CASE
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WHEN MAX(y.level) IS NULL THEN x.access_level_default
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ELSE MAX(y.level)
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END
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) AS access_level
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FROM
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calendars AS x
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LEFT OUTER JOIN calendar_access_attributed AS y ON ((x.id = y.calendar_id) AND (y.user_id = $user_id))
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GROUP BY
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x.id
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HAVING
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(access_level > 0)
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ORDER BY
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access_level,
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id
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;
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